Kata

Given the molecular mass of two molecules $M_{1}M\_1$ and $M_{2}M\_2$, their masses present $m_{1}m\_1$ and $m_{2}m\_2$ in a vessel of volume $VV$ at a specific temperature $TT$, find the total pressure $P_{total}P\_\{total\}$ exerted by the molecules. Formula to calculate the pressure is:

Input

Six values :

• $M_{1}M\_1$, $M_{2}M\_2$: molar masses of both gases, in $g\cdot mo{l}^{-1}\backslash \; g\; \backslash cdot\; mol^\{-1\}$
• $m_{1}m\_1$ and $m_{2}m\_2$: present mass of both gases, in grams ($gg$)
• $VV$: volume of the vessel, in $d{m}^3\backslash \; dm^3$
• $TT$: temperature, in $\mathrm{°}C\backslash \; \backslash degree\; C$

Output

One value: $P_{total}P\_\{total\}$, in units of $atmatm$.

Notes

Remember: Temperature is given in Celsius while SI unit is Kelvin ($KK$). $0\mathrm{°}C=273.15K\backslash \; 0\backslash degree\; C\; =\; 273.15K$

The gas constant $R=0.082d{m}^3\cdot atm\cdot K^{-1}\cdot mo{l}^{-1}\backslash \; R\; =\; 0.082dm^3\; \backslash cdot\; atm\; \backslash cdot\; K^\{-1\}\; \backslash cdot\; mol^\{-1\}$